2x+2y=38
y=x+3
First you would substitute the y for x+3
2x+2(x+3)=38
You would multiply the 2 by the x+3
2x+2x+6=38
Add the 2x and the 2x
4x+6=38
Subtract the 6 on both sides
4x=32
Divide the 4 on both sides
x=8
Now substitute the x in the second problum for 8
y=8+3
Add the 8 and the 3 to solve for y
y=11
Your answers
x=8
y=11
the correct answer would be A:(8,11)
I believe Qualitative Quantitative Discrete (Continuous is like 1/3 it's .33333333 and it goes on forever)
50 meters/27.5 seconds = 1.818 meters /sec
Answer:
D
Step-by-step explanation:
To be an identity we require both sides of the equation to equate
A
8x + 9 ≠ 8x - 3 ← not an identity
B
7x - 2 = 8x + 4 - x = 7x + 4 ≠ 7x - 2 ← not an identity
C
11 - (2x + 3) = 11 - 2x - 3 = - 2x + 8 ≠ - 2x - 8 ← not an identity
D
5x + 8 - x = 6x - 2(x - 4), that is
4x + 8 = 6x - 2x + 8 = 4x + 8 ← both sides equate thus an identity
