Answer:
28°
Step-by-step explanation:
You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.
<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y
0=b+1-c --- equation 2
According to multiple rule of Differentiation,
so, we get
By putting value of point A and putting value of eq 2 we get
Hence proved that the gradient of the curve at A is 1.
The volume is 13*7*5. Therefore, the answer is 455 in^3
Answer:
444 adult ticket
763 student ticket
Step-by-step explanation:
let a = number of adult ticket
let s = number of student ticket
s+a=1207
5a+s=2983
get s by itself in the 1st equation so you can plug it into the 2nd
s+a=1207
-a -a
s=1207-a
5a+(1207-a)=2983
solve for a
4a+1207=2983
-1207 -1207
4a= 1776
444
this is adult ticket amount
subtract this from 1207 to get student amount
1207-444=763
