Carbon dioxide and oxygen
A would have it.
A is hetrozygous person. Since it is dominant, you only need 1 "H" to recieve the gene. Since B has two "h", it would not contain the disease.
Answer:b. cellulose; cell walls of plants
Explanation: polysaccharides are polymers of monossacharides.they are the most abundant organic substance.it is found in the cell walls of plants . cellulose is a linear polymer of glucose residues.cellulose is an important component in the diet of herbivores and omnivores.they do not produce the cellulase enzyme for digesting cellulose.as a result,they depend on symbiotic relationship with bacteria and protozoa found in their stomach to produce cellulase.
D. Limber Pine Trees is the correct answer
Mushrooms are decomposers, pine martins and snowshoe hairs are both consumers, so that leaves you with limber pine trees.
Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE