Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Gradient is the slope, which is the letter m in the equation.
The point is written as (x1, y1) so replace x1 and y1 in the equation with the numbers in the given point.
A would be y - 1= 2(x-4)
B: y +5 = 5(x-2)
C: y-1= -3(x+1)
D: y -6 = 1/2(x-1)
E: y +1/4 = -2(x-3:4)
F: y+7 = -1/5(x+ 3)
Seven and twenty five hundredths, or seven and a quarter
X=2/3y because you want to know what roberts time is
Its c 10 and other fillar so i can answer
