The graph shows the fisrt four pattern oredered pairs foremed by the corresponding terms of two paterrens 1 SEE ANSWER

2 answers:

4 0

Answer: If you could add the graph to your question so I can see what it looks like, that would be great! I would probably be able to answer it, then. :)

Step-by-step explanation:

LenaWriter [7]2 years ago

3 0

I need more information to be able to answer this sorry

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Francis went to the sporting goods store and spent $75.15 on 6 items.

MArishka [77]

Answer:

$6.03

Step-by-step explanation:

The question is asking us how much each pair of socks cost. With the information we are given, we know that there are 5 pairs and that they all cost the same amount. If the total were just the 5 socks, we could easily divide the total by 5 to get the price of each pair but that's not the case. The soccer ball is included in the final cost. To overcome this, we just have to subtract the soccer ball's cost ($45) from the total.

So we subtract $45 from $75.15, giving us $30.15, the total amount of all the socks. However we need to find out how much each pair costs and there are 5 of them, so we divide 30.15 by 5. This gives us the answer, $6.03.

Each pair of socks cost $6.03.

Simpler Explanation:

$75.15 - $45 = $30.15
$30.15 / 5 = $6.03

The answer is $6.03

5 0

2 years ago

Work the following problem

neonofarm [45]

Answer:

Option B is the correct answer.

Step-by-step explanation:

Given

List Price=$720

The percentage of discount=13%

In order to find the amount of discount, 13% of the amount has to be calculated. To calculate 13% , the amount is multiplied by 13/100.

Amount of discount=13% of list price

=720*13/100

=720*0.13

=$93.60

The amount of discount is $93.6..

5 0

3 years ago

A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan

svlad2 [7]

Answer:

$t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$

Step-by-step explanation:

We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.