9514 1404 393
Answer:
F
Step-by-step explanation:
If the circle is tangent to the x-axis at 4, the center lies on the line x=4.
If the circle is tangent to the y-axis at 4, the center lies on the line y=4.
If the center of the circle is (x, y) = (4, 4) and it is tangent to the axes, then the radius is 4.
The standard-form equation of the circle centered at (h, k) with radius r is ...
(x -h)² +(y -k)² = r²
For the values (h, k) = (4, 4) and r = 4, the equation is ...
(x -4)² +(y -4)² = 16 . . . . . . matches choice F
25x+ the diameter of a rectangle
Yes. They are both right.
Answer:
The answers are that a = -5 and b = 1
Step-by-step explanation:
In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)
m(slope) = (y2 - y1)/(x2 - x1)
m = (11 - 5)/(-3 - 0)
m = 6/-3
m = -2
Now that we have this we can model this using point-slope form.
y - y1 = m(x - x1)
y - 5 = -2(x - 0)
y - 5 = -2x
y = -2x + 5
Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.
y = -2x + 5
15 = -2(a) + 5
10 = -2a
-5 = a
And we can also solve for b using the ordered pair (2, b)
y = -2x + 5
b = -2(2) + 5
b = -4 + 5
b = 1
<span>Yes it is true that a continuous function that is never zero on an interval never changes sign on that interval. This is because of ever important Intermediate Value Theorem.</span>
