Answer:
The speed of the block is 4.96 m/s.
Explanation:
Given that.
Mass of block = 1.00 kg
Spring constant = 500 N/m
Position
Coefficient of friction = 0.350
(A). We need to calculate the speed the block has as it passes through equilibrium if the horizontal surface is friction less
Using formula of kinetic energy and potential energy
Put the value into the formula
Hence, The speed of the block is 4.96 m/s.
Answer:
Cp = 4756 [J/kg*°C]
Explanation:
In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.
Q = m*Cp*(T_f - T_i)/t
where:
Q = heat transfer = 2.6 [kW] = 2600[W]
m = mass of the water = 0.8 [kg]
Cp = specific heat of water [J/kg*°C]
T_f = final temperature of the water = 100 [°C]
T_i = initial temperature of the water = 18 [°C]
t = time = 120 [s]
Now clearing the Cp, we have:
Cp = Q*t/(m*(T_f - T_i))
Now replacing
Cp = (2600*120)/(0.8*(100-18))
Cp = 4756 [J/kg*°C]
Induced electromotive force
146 million kilometers or 92.96 million miles away!
Answer:
the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev
Explanation:
Given;
Angular velocity v = 33.9 rad/s
Time t = 92.1 s
Angular displacement d = angular velocity × time
d = vt
Substituting the given values;
d = 33.9 × 92.1 rad
d = 3122.19 rad
To revolutions;
revolution = radian/2π
d = 3122.19/2π rev
d = 496.91 rev
the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev