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That's at least one of his parents are heterozygous
The right answer is 5.
To answer this question it is sufficient to take the same approach as the one that concluded that each amino acid is equivalent to 3 codons.
We have 17 amino acids, each of which must have at least one unique code (having two nucleotides A and T)
.
it is enough to apply this time to count the number of possible codons to be generated according to the number of nucleotides:
nucleotide set ^ number of nucleotides = number of codons
.
2 ^ 1 = 2 (<17)
2 ^ 2 = 4 (<17)
2 ^ 3 = 8 (<17)
2 ^ 4 = 16 (<17)
2 ^ 5 = 32 (> 17)
So, each amino acid has a codon of 5 nucleotides.
C I believe because they are living so they are able to breath
A is the answer to this problem
