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2 years ago

- 24 divided by 6 = ?

Mathematics

2 answers:

liubo4ka [24]2 years ago

7 0

Answer:

-4

Step-by-step explanation:

-24÷6 =-4

to double check you can do 6×-4 and you would get -24

hope this helps!

Nady [450]2 years ago

6 0

Answer:

-4

Step-by-step explanation:

-24/6=-4

a negative divided or multiplied by a positive is a negative

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A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

Fynjy0 [20]

Answer:

The equation showing this situation is $D=b^2-4ac=0$

Step-by-step explanation:

Given : A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

To find : Which could be the equation?

Solution :

A quadratic equation in form $ax^2+bx+c=0$ has a solution $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If $D=b^2-4ac>0$ there are two real roots.

2) If $D=b^2-4ac=0$ there are one real roots.

3) If $D=b^2-4ac$ there are no real roots.

According to question,

A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

So, The equation showing this situation is $D=b^2-4ac=0$

6 0

2 years ago

You have a 1 in 4 chance of winning a game. How would you calculate the probability that you will win 3 times in a row?

Ierofanga [76]

Answer:

<u>The probability of winning three games in a row is 1/64 or 1.6%</u>

Step-by-step explanation:

Probability of winning a game = 1/4

Probability of winning two games in a row = 1/4 * 1/4 = 1/16

Probability of winning three games in a row = 1/4 * 1/4 * 1/4 = 1/64

Probability of winning three games in a row = (1/4)³ = 1/64

1/64 = 0.015625

1/64 = 1.6% (rounding to the next tenth)

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2 years ago

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Answer:

1661.9

Step-by-step explanation:

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2 years ago

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Andreas93 [3]

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6 0

2 years ago

Find two positive integers that satisfy the requirement.

aleksandr82 [10.1K]

Answer:

The two positive integers that satisfy the requirement are 21 and 23

Step-by-step explanation:

Let

x ----> the first consecutive odd integer

x+2 ---> the second consecutive odd integer

we know that

$x(x+2)=483$

Apply distributive property left side

$x^2+2x=483$

$x^2+2x-483=0$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+2x-483=0$

$a=1\\b=2\\c=-483$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^{2}-4(1)(-483)}} {2(1)}$

$x=\frac{-2(+/-)\sqrt{1,936}} {2)}$

$x=\frac{-2(+/-)44} {2)}$

$x=\frac{-2(+)44} {2)}=21$

$x=\frac{-2(-)44} {2)}=-23$

x=21

x+2=23

therefore

The two positive integers that satisfy the requirement are 21 and 23

6 0

2 years ago