When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>
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In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.
In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>
It can be written as
→
When it will be heated then it gives methyl vinyl ketones.
→
So, the pair of reactants will be formaldehyde and acetone
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Answer:
The mixture is not in equilibrium, the reaction will shift to the left.
Explanation:
<em>Based on the equilibrium:</em>
<em>Fe³⁺+ HSCN ⇄ FeSCN²⁺ + H⁺</em>
<em>kc = 30 = [FeSCN²⁺] [H⁺] / [Fe³⁺] [HSCN]</em>
Where [] are concentrations at equilibrium. The reaction is in equilibrium when the ratio of concentrations = kc
Q is the same expression than kc but with [] that are not in equilibrium
Replacing:
Q = [10.0M] [1.0M] / [0.1M] [0.1M]
Q = 1000
As Q > kc, the reaction will shift to the left in order to produce Fe³⁺ and HSCN untill Q = Kc
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Answer:
38 kg/m³
0.038 g/mL
Explanation:
Volume of a cube is the side length cubed.
V = s³
Given s = 0.65 m:
V = (0.65 m)³
V ≈ 0.275 m³
The mass is 10.5 kg. The density is the mass divided by volume:
ρ = (10.5 kg) / (0.275 m³)
ρ ≈ 38 kg/m³
Or:
ρ ≈ 0.038 g/mL
4 protons are there in the atom
The greatest molar amount of metal product is obtained from silver (1) nitrate.
Let us determine the mass of metal obtained in each case.
For La^3+;
La^3+ + 3e ----> La
1 mole of La is deposited by 3F
x moles of La is deposited by 10 F
x = 1 × 10/3
x = 3.33 moles
For Zn^2+;
1 mole Zn^2+ is deposited by 2F
x moles of Zn^2+ is deposited by 10 F
x = 5 F
For Ag^+
1 mole of Ag^+ is deposited by 1 F
x moles of Ag^+ is deposited by 10 F
x = 10 moles
For Ba^2+;
1 mole of Ba^2+ is deposited by 2 F
x moles of Ba^2+ is deposited by 10 F
x = 5 moles
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