Answer:
Explanation:
Alcohols are organic compounds that are composed of the hydroxyl function group (
), bonded to a carbon atom of an alkyl or a substituted alkyl group. Hence, the functional group of alcohols is the hydroxyl group ().
According to the International Union of Pure and Applied Chemistry (IUPAC) nomenclature, alcohols are named by changing the -<em>e</em> ending of the name of the parent alkane to the suffix <em>-</em><em>ol</em>.
For example, the alcohol molecule in the figure demonstrates a hydroxyl group bonded to a methyl group. Therefore, the name of the alcohol is methanol.
An intensive property is the physical characteristics that have an independent magnitude. The thermometer can be used to measure the temperature. Thus, option C is correct.
<h3>What is an intensive property?</h3>
An intensive property has been constituted of the parameters that are not dependent on the size and the mass of the sample. Density, pressure, and temperature are some intensive properties.
The first image shows a weighing balance, the second shows a volumetric cylinder, and the fourth shows a ruler used to measure mass, volume, and length respectively, which are extensive properties.
Therefore, option C. thermometer measures temperature, which is an intensive property.
Learn more about the intensive property here:
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Answer:
10−8 M.
Explanation:
In this problem we are given pH and asked to solve for the hydrogen ion concentration. Using the equation, pH = − log [H+] , we can solve for [H+] as,
− pH = log [H+] ,
[H+] = 10−pH,
by exponentiating both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,
[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × In this problem we are given pH and asked to solve for the hydrogen ion concentration. Using the equation, pH = − log [H+] , we can solve for [H+] as,
− pH = log [H+] ,
[H+] = 10−pH,
by exponentiating both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,
[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × 10−8 M.
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
</span><span>E = +1.47
</span>
<span>Br(l) + 2e- = 2Br-
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
