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BabaBlast [244]

2 years ago

12

What is the ratio value shown by this double number line?

1 answer:

OlgaM077 [116]2 years ago

5 0

The answer is 21/6

Explanation: the next number in the pattern would be 21 since this is linear

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Abby earns $48 for babysitting for 6 hours . At that rate , how many hours will it take her to make $72

never [62]

Answer:

nine hours

Step-by-step explanation:

48 divided by 6 is 8 and 8 times 9 is 72

8 0

2 years ago

Read 2 more answers

A fruit market received a shipment of apples. The market sold them in bags with 14 apples in each bag. It sold 24 bags of apples

agasfer [191]

The answer is 462 apples was in the shipment or 33 bags!
1 bag = 14 apples
24 bags sold = 336 apples

126 apples was not sold = 9 bags

24 bags + 9 bags = 33 bags
33 bags * 14 apples/per bags = 462 apples

5 0

2 years ago

Read 2 more answers

A cylinder has a volume of 2167 cubic feet and a height of 18 feet What is the area of the base?

natita [175]

Answer:

120.39ft²

Step-by-step explanation:

Hopefully that helps :)

6 0

2 years ago

Did I get this right?

wel

Yes hope it helps!!!!!!!!

4 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

1 year ago