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2 years ago

Solve for p.1/3(4p-9)=8p+12

Mathematics

2 answers:

antoniya [11.8K]2 years ago

7 0

P = -9/4.
Hope this helps! If you need an explanation or further assistance, comment under this post of message me!

ludmilkaskok [199]2 years ago

3 0

P = -9/4
That is the answer

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Uh can someone please help? please get it right and try to explain how

Anestetic [448]

Answer:

From least likely to most likely:

Colorado Bronze wins

I Am Pat wins

Good Legs Lance wins

Step-by-step explanation:

Converting all probabilities to the same type may be easier to visualize and see the chances. Let's convert each chance to percentage:

P(I Am Pat wins) = 3/10 = 30%

P(Good Legs Lance wins) = 0.6 = 60%

P(Colorado Bronze wins) = 10%= 10%

Thus, the desired order is:

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2 years ago

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1220000 scientific notation

Nutka1998 [239]

Answer:

1.22 x $10^{6}$

Step-by-step explanation:

1,220,000 would be...

1.22 x 10^6

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2 years ago

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Which linear inequality is represented by the graph

levacccp [35]

Answer:

The correct awnser is A : )

Step-by-step explanation:

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1 year ago

What is -3.75 in the simplest form

NARA [144]

There is no simplest form for a decimal. You can only simplify equations and fractions, not decimals. For example, could you simplify 1? I don't think you could. Well, it's the same concept for -3.75.
Hope that answered your question.

5 0

2 years ago

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice

Svet_ta [14]

Answer:

a.) P(x = X) = $\frac{1}{50}$

b.) $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $\frac{1}{50}$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}\times \frac{1}{50} \times \frac{1}{50}\times \frac{49}{50}) + (\binom{3}{3}\times \frac{1}{50} \times \frac{1}{50}\times \frac{1}{50})\\$

= $\frac{147}{125000} + \frac{1}{125000}$

= $\frac{148}{125000}$

= 0.00118

7 0

2 years ago