Answer:
new force is 6 times of the initial force.
Explanation:
Let the charges on two objects is q₁ and q₂. The electric force between charges is given by :
Objects 1 and 2 attract each other with a electrostatic force of 18.0 units
If the charge of Object 1 is doubled and the charge of object 2 is tripled, it means, and . New force is given by :
So, the new electrostatic force between objects will become 6 times of the initial force.
Answer:
The actual elevation angle is 12.87 degrees
Explanation:
In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that .
Using Snell's Law we can write:
,
Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.
We thus have:
. Calling the actual angle of elevation, we get from the picture that
The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ
First, we must understand that the component of the velocity along the vertical is due to maximum height achieved and expressed as usin
θ.
The component of the velocity along the horizontal is due to the range of the object and is expressed as ucosθ.
If the <u>air resistance is ignored</u>, the velocity of the object will be constant throughout the flight and the initial velocity will be equal to the final velocity.
Hence the required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ
Learn more here; brainly.com/question/12870645
Answer:
10miles/second
Explanation:
Change in velocity of the bird is expressed as the difference between the final velocity and initial velocity of the body.
Change in velocity = Final velocity - initial velocity
Since the bird takes off from the tree, the initial velocity of the bird = 0miles/sec
Final velocity = 10miles/secs
Change in velocity = 10-0
Change in velocity = 10miles/second
Explanation:
<h2> Answers</h2>
1.Electromagnetic waves
2.Electromagnetic radiation
3.Electromagneticwaves