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2 years ago

A group of students are playing tug-of-war. The students on both

Physics

1 answer:

Andrews [41]2 years ago

7 0

Answer:

newton's first law

Explanation:

this is because newton's first law of motion states that every object will continue in its state of rest or uniform motion in a straight line unless a resultant force acts on it.

hope this helps, if you want more elaboration, tell me

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What is lever means,types of lever.. will give brainles

serious [3.7K]

Explanation:

A lever is a rigid bar which moves freely about a fixed point called fulcrum....

The types of lever are :

First class lever
Second class lever
Third class lever....

3 0

1 year ago

What is most likely the color of the light whose second-order bright band forms an angle of 13.5° if the diffraction grating has

mash [69]

Answer:

the color is red.

8 0

2 years ago

Read 2 more answers

Use what you know about reflection and absorption of light to complete the sentence.

Blababa [14]

A red ladybug appears red in white light, red in red light, and black in blue light. Those would be the proper selections you'd need.

3 0

2 years ago

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What is the acceleration of an object with a constant velocity

valina [46]

Zero.

Acceleration is defined as the change in velocity over time.

Since in your case there is no change, there is no acceleration, so it is zero:

Or in formula: a=Δvt

Where a=acceleration, Δv=change in velocity and t=time

6 0

2 years ago

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A musician on a unicycle is riding at a steady 6.2 m/s while playing their well tuned oboe at an A above middle C (440 Hz). They

Verizon [17]

Answer:

The frequency of the beat is $f_t = 8Hz$

Explanation:

From the question we are told that

The speed of the ride $v = 6,2 m/s$

The frequency of the oboe is $f = 440Hz$

The temperature outside is $T = 27^oC$

Generally the speed of sound generated in air is mathematically evaluated as

$v_s = 331 + 0.61 T$

Substituting value

$v_s = 331 + 0.61 *27$

$v_s = 347.47 \ m/s$

The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as

$f_a = \frac{v_s }{v_s - v} f$

substituting values

$f_a = \frac{347.47 }{347.47 - 6.2} * 440$

$f_a = 448Hz$

Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is = 440Hz

The beat frequency these musician here is mathematically evaluated as

$f_t = f_a - f$

So $f_t = 448 - 440$

$f_t = 8Hz$

3 0

2 years ago