Answer: So if you had 570 cm of ribbon, then 570%2F8.5=67.05 which means that about 67 students can do the experiment (round down to the nearest whole number).
Explanation: If you had 8.5 cm of ribbon, then only 8.5%2F8.5=1 student can do the experiment. If you had 17 cm of ribbon, then 17%2F8.5=2 students can do the experiment.
Answer:
G<0, spontanteous
H<0, from equation
S>0, gas to solid
Explanation:
The small bags of silica gel you often see in a new shoe box are placed there to control humidity. Despite its name, silica gel is a solid. It is a chemically inert, highly porous, amorphous form of SiO2. Water vapor readily adsorbs onto the surface of silica gel, so it acts as a desiccant. Despite not knowing mechanistic details of the adsorption of water onto silica gel, from the information provided, you should be able to make an educated guess about the thermodynamic characteristics of the process. Predict the signs of ΔG, ΔH, and ΔS.
G<0, spontanteous
H<0, from equation
S>0, gas to solid
The question is incomplete. Complete question is attached below:
...........................................................................................................................
Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
Answer:
0.960 m
Explanation:
Given data
- Mass of the solute: 27.9 g
- Molar mass of the solute: 233.2 g/mol
- Mass of the solvent: 125.0 g = 0.1250 kg
First, we will calculate the moles of solute.
27.9 g × (1 mol/233.2 g) = 0.120 mol
The molality of the compound is:
m = moles of solute / kilograms of solvent
m = 0.120 mol / 0.1250 kg
m = 0.960 m
<span>For number
two, the equation is balanced. Na in the reactant side has one atom and also in
the product side. O has only one atom in the product and in the reactant. There
are 2H’s in the reactant and in the product side (present in H2O, the 2 in H
stands for 2 atoms of H). One atom of Cl is present in the reactant and product
side.</span>
For number
three, the reactants are NaOH-sodium hydroxide and HCl-hydrogen
chloride(hydrochloric acid). The products are NaCl-sodium chloride and
H2O-water.