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1 year ago

PLEASE HELP!!!! The quadratic functions f(x) and g(x) are described as follows: f(x) = -2x ^ 2 + 9

Mathematics

1 answer:

VladimirAG [237]1 year ago

8 0

Answer:

g(x) has a greater maximum value than f(x).

Step-by-step explanation:

I just took the test!

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2 years ago

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Step-by-step explanation:

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1 year ago

Help with this math question

tresset_1 [31]

The given inequality is:

$|-8x+24| \leq 16$

This inequality can be divided in two parts as:

a) $-16 \leq -8x +24$
b) $-8x + 24 \leq 16$

Solving part a:

$-16 \leq -8x+24 \\ \\ 
-40 \leq -8x \\ \\ 
5 \geq x \\ 
or \\ 
x \leq 5$

Solving part b:

$-8x+24 \leq 16 \\ \\ 
-8x \leq -8 \\ \\ 
x \geq 1$

Therefore, the solution to the given inequality is $x \leq 5$ and $x \geq 1$ . Combining both the ranges we get the solution: $1 \leq x \leq 5$ .

In interval notation, this solution can be expressed as [1,5]

3 0

2 years ago

Read 2 more answers

Classify each number below as an integer or not.

fomenos

Answer:

1. yes

2. no

3. yes

4. no

5. yes

Step-by-step explanation:

The method i use is if the number is not a fraction than it is an integer. besides 6 for some reason.

Here is the catch if the fraction can be simplified into a whole number than it is an integer.

6 0

2 years ago

PLEASE HELP Which expression represents the difference quotient of the function f (x) = negative StartRoot 2 x EndRoot?

natali 33 [55]

Answer:

c is the correct option

Step-by-step explanation:

from,

f'(x) = h >0 f(x + h) - f(x)

f(x) = - √2x

f(x + h) = - √(2x + h)

f'(x) = h>0 -√(2x + h) - √2x

rationalize the denominator

= h>0 -√(2x + h) + √2x (-√(2x + h) - √2x)

h (-√(2x + h) - √2x)

= h>0 4x + 2h - 4x

h(-√(2x + h) -√2x)

= h>0 2h

h(-√(2x+h) - √2x)

= h>0  2 

-√(2x+h) - √2x

5 0

2 years ago

Read 2 more answers