Evaluate the definite integral. 1 3ti + 7t3j + 3 t k dt −1
1 answer:
It would be so much clearer if you'd please put parentheses around the t-functions:
<span>Evaluate the definite integral. (1/3)t i + (7t)^3 j + (3t) k dt
Also , there should be a set of brackets or parentheses around
</span>(1/3)t i + (7t)^3 j + (3t) k. And, finally, we need an explanation of your −1. I do not recognize it at all.
To find the indefinite integral of [ (1/3)t i + (7t^3) j + (3t) k ]dt
integrate term by term:
(1/3)(t^2)/2) i + 7*t^4/3 j + (3*t^2/2) k + c
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