<u>Given</u>:
Given that ABC is a right triangle.
The length of AB is 7 units.
The measure of ∠A is 65°
We need to determine the length of AC
<u>Length of AC:</u>
The length of AC can be determined using the trigonometric ratio.
Thus, we have;
Where the value of is 65° and the side adjacent to the angle is AC and the side hypotenuse to the angle is AB.
Substituting the values, we have;
Substituting AB = 7, we have;
Multiplying both sides by 7, we get;
Rounding off to the nearest hundredth, we get;
Thus, the length of AC is 2.96 units.
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Answer:
5n+5
Step-by-step explanation:
5(n+3)-10
5n+15-10
5n+5
The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²