Answer:
22.75 minutes or 22 minutes 45 seconds
Step-by-step explanation:
Okay, this is a working together question. Let’s walk through it together!
Firstly, let’s say the total volume of the swimming pool is x sq.meters
Now, the rate of the smaller hose would be x/65 while that of the larger will be x/35
Now, their combined rate would be x/65 + x/35 = 100x/2275
Now, since the volume is x, the time taken is simply, the volume divided by the joint rate. That is mathematically equal to x divided by 100x/2275
x * 2275/100x = 2275/100 = 22.75 minutes or 22 minutes 45 seconds
Answer:
B
Step-by-step explanation:
10 yards. The amount of yards is 1 third the amount of feet so you just divide 30 by 3 to get the amount of yards
Answer:
40 student 110 adult
this is using desmos
but to smash the equation you can go like basically we have to cancel out each variable to solve for the other
3x + 8y = 1000
x + y < =150
-3(x + y <= 150)
-3x -3y = -450
3x + 8y = 1000
5y = 550
y= 110
3x + 8 y = 1000
-8(x+y<=150) = -8x - 8y <= -1200
-5x = -200
x= 40
40 kids 110 adults