Answer:
22.75 minutes or 22 minutes 45 seconds
Step-by-step explanation:
Okay, this is a working together question. Let’s walk through it together!
Firstly, let’s say the total volume of the swimming pool is x sq.meters
Now, the rate of the smaller hose would be x/65 while that of the larger will be x/35
Now, their combined rate would be x/65 + x/35 = 100x/2275
Now, since the volume is x, the time taken is simply, the volume divided by the joint rate. That is mathematically equal to x divided by 100x/2275
x * 2275/100x = 2275/100 = 22.75 minutes or 22 minutes 45 seconds