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2 years ago

Solve the inequality 5p -3 < 7 + 3p for p

Mathematics

1 answer:

KiRa [710]2 years ago

5 0

Step-by-step explanation:

p<5 that's the answer for the question

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HELPPPP ASAPPP PLEASSSSEE

kolezko [41]

Let dimes = d and quarters =q

D + q = 50

D= 50-q

0.10d + 0.25Q = 7.70

Replace d with 50-q:

0.10(50-q) + 0.25q = 7.70

Simplify:

5 -0.10q + 0.25q = 7.70

5 + 0.15q = 7.70

Subtract 5 from both sides:

0.15q = 2.70

Divide both sides by 0.15:

Q = 2.70 / 0.15

Q = 18

D = 50-18 = 32

There are 32 dimes and 18 quarters

5 0

2 years ago

Read 2 more answers

Please help I’ll give brainlyist

lakkis [162]

Answer:

The second choice

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A company wants to evaluate its attrition rate, in other words, how long new hires with the company. Over the years, they have e

nlexa [21]

Answer:

2.) 0.10 (3.) 0.10 (4.) 2.43

Step-by-step explanation:

Given that:

x p(x)

0 0.12

1 0.18

2 0.30

3 0.15

5 0.10

6 0.05

X : __0__ 1 ___ 2 ___ 3 _____ 4 ____ 5 ____ 6

p(x):0.12_0.18_0.30_0.15__0.10___0.10 ___0.05

Σ of p(x) = 1

(0.12 + 0.18 + 0.30 + 0.15 + x + 0.10 + 0.05) = 1

0.9 + x = 1

x = 1 - 0.9

x = 0.1

2.)

P(x = 4) = 0.10

3.)

P(x = 5) = 0.10

4.)

Σ(x * p(x)) :

(0*0.12) + (1*0.18) + (2*0.3) + (3*0.15) + (4*0.1) + (5*0.1) + (6*0.05) = 2.43

7 0

2 years ago

PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.

Step2247 [10]

After using the property of power, the expressions as a power of the number a is $(a^3)^{-2} = a^{-6}$ , $(a^{-1}\cdot a^{-2})^{-3} = a^{9}$ and $((a^2)^{-2})^2=a^{-8}$ .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is $(a^3)^{-2}$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

Simplifying the expression.

$(a^3)^{-2} = a^{3*(-2)}$

$(a^3)^{-2} = a^{-6}$

The second expression is $(a^{-1}\cdot a^{-2})^{-3}$

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}$

Using the property of sum of power $a^m\cdot a^n=a^{m+n}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{9}$

The third expression is $((a^2)^{-2})^2$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=((a^2)^{(-2)\times2})$

$((a^2)^{-2})^2=(a^2)^{-4}$

Again using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=a^{2\times(-4)}$

$((a^2)^{-2})^2=a^{-8}$

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0

7 months ago

PLEASE HELP THIS IS DUE ASAP AND I WILL MARK U BRAINLIEST

suter [353]

Answer: 4/1

Step-by-step explanation:

Rise over run. Starting at 1 on the y axis this line moves up 4 and over (right) 1 before it hits 1 on the x axis.

7 0

2 years ago