Answer:
42.64°
Step-by-step explanation:
Note: A rhombus has all its sides equal, its opposite angle are equal, its has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.
From the diagram attached,
sinθ = opposite/adjacent
sinθ = 4/11
θ = sin⁻¹(4/11)
θ = 21.32
Therefore, from the diagram,
The smaller angle of the rhombus = 2θ
The smaller angle of the rhombus = (2×21.32)
The smaller angle of the rhombus = 42.64°
Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
0.5a - 0.3 = 5
Add 0.3 to both sides:
0.5a = 5.3
Divide both sides by 0.5:
a = 10.6
Trapezoids always have 4 sides, so this is true. All rhombuses have parallel sides, so B is true also. A trapezoid has two sides that are not parallel, so C is not true. (remember, you only have to find one instance where your statement is false for it to be false) And for D, all rhombuses are kite-shaped so D is not true. A and B are true. Hope this helps. :)