What is true about warming up?

Physics

1 answer:

Alja [10]2 years ago

5 0

Answer:

D. All of the above

Explanation:

I would know cuz I'm in Track. Hope this helped, Have a Great Day!!

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Name the characteristics of electro magnetic waves that i) increases ii) remains constant in the electromagneticspectrum as one

Paul [167]

As we move from Radiowaves to UV waves in electromagnetic spectrum we know that the wavelength is maximum for radio waves while its frequency is minimum

PART (i)

So as we move from radiowaves to UV region

the Frequency will increase

Part (ii)

As we move from Radiowaves to UV region all the parts must have same speed in same medium

All parts will move with speed of light

so Speed will remain the same

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3 years ago

What is the specific heat of an unknown substance if 2000 J of energy are required to raise the temperature of 4 grams of the su

Dmitriy789 [7]

The energy required to heat a substance is related by the formula:
Q = mCpΔT ; where Q is the energy, m is the mass of the substance, Cp is the specific heat capacity and ΔT is the change in temperature.
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2 years ago

Captain John Stapp is often referred to as the "fastest man on Earth." In the late 1940s and early 1950s, Stapp ran the U.S. Air

valentina_108 [34]

Answer:

The sled needed a distance of 92.22 m and a time of 1.40 s to stop.

Explanation:

The relationship between velocities and time is described by this equation: $v_f=v_0+a*t$ , where $v_f$ is the final velocity, $v_0$ is the initial velocity, $a$ the acceleration, and $t$ is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: $t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s} }{-201\frac{m}{s^2} }=1.40s$ , where $v_f=0\frac{m}{s}$ because the sled is totally stopped, $v_0=282\frac{m}{s}$ is the velocity of the sled before braking and, $a=-201\frac{m}{s^2}$ is negative because the deceleration applied by the brakes.

In the other hand, the equation that describes the distance in term of velocities and acceleration: $x_f-x_0=v_0*t+\frac{1}{2}*a*t^2$ , where $x_f-x_0$ is the distance traveled, $v_0$ is the initial velocity, $t$ the time of the process and, $a$ is the acceleration of the process.