To develop the problem it is necessary to apply the equations related to the moment of inertia.
The given values can be defined as,
According to the definition of the moment of inertia applied to the exercise we can arrive at the equation that,
Where n is the number of spokes necessary to construct the wheel.
Replacing the values at the general equation we have,
Solving for n,
Therefore the number of spokes necessary to construct the wheel is 36
PART B) The mass of the wheel is given by the sum of all masses and the total spokes, then
Therefore the mass of the wheel must be of 1.36Kg
Answer:
49.85 V
Explanation:
u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s
Let the electric field is E and voltage is V.
Use second equation of motion
s = ut + 1/2 a t^2
5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2
a = 8.5 x 10^10 m/s^2
m x a = q x E
E = m x a / q
E = (1.67 x 10^-27 x 8.5 x 10^10) / (1.6 x 10^-19)
E = 887.19 V/m
V = E x s
V = 887.19 x 5.62 x 10^-2 = 49.85 V
4. KE increases by a factor of 16 is the answer
<u>Explanation:</u>
Kinetic energy = (1/2)mv² = 0.5 mv²
where
m = mass, and v = velocity.
So at 15 mph,
K
E = 0.5 m (15)
² = 112.5 m
And at 60 mph,
K
E = 0.5 m (60)² = 1800 m
m is the mass, and not meters.
So, 1800 m/112. 5 m = 16
16 times the Kinetic Energy.
A) F1/A1=F2/A2
F2 = 12000 Newtons, while F1 = 400 Newtons and area A1= 6 cm²
400/6 = 12000/A2
A2 = (6 × 12000)/400
= 180 cm²
b) How long does this lift the car
d2 =F1/F2×d1
= (400/12000)× 20
= (1/30)×20
= 20/30
= 0.67 cm
This lifts the car a distance of 0.67 cm
