Answer:
Step-by-step explanation:
Plot the points x-intercept and intercept on the graph. Join the two points to get the straight line. This is the graph of the linear equation.
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.
Let x be the number of $2 increases in price, then the revenue from renting cars is given by
.
Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>
For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>
The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.
Therefore, the </span><span>rental charge will maximize profit is $64.</span>
Answer:
10
Step-by-step explanation:
Firstly, AM=x+8
or, A=x+8-M......eqn (i)
MB=6x-2
or, B=6x-2-M......eqn (ii)
Now,
from eqn (i) and (ii)
x+8-M=6x-2-M
or, 8+2=6x-x-M+M
or, 10=5x
or, 10÷5=x
therefore, x=2
Again,
MB=6x-2
=6×2-2
=12-2
=10
is it correct
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Answer:
5x + 2y = 3280
x+y = 785
x = 785 - y
5*(785 - y) + 2y = 3280
3925 - 5y + 2y = 3280
3925 - 3280 - 3y = 0
645 = 3y
y=645/3=215
x=785-215 = 570
Adults - 570 tickets, childs - 215 tickets.
570*5 + 215*2 = 3280
570 adult and 215 child and 3,280 in total
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