The two electrons in a helium atom occupy

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

$C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g$

To know the percent of each element, we need to to the following:

$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0

2 years ago

Which of the following terms best describes an atom which is chemically unreactive?

frez [133]

I think it is full because an atom is really small and can’t really be unreactive

7 0

2 years ago

Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad

S_A_V [24]

Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
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3 0

2 years ago

Write the balanced electrochemical reaction for when zinc reacts with a copper solution. Label what is being oxidized and what i

Fed [463]

The balanced equation would be $Zn + Cu^{2+} ---- > Cu + Zn^{2+}$

<h3>Electrochemical equations</h3>

Zn reacts with Cu solution according to the following equation:

$Zn + Cu^{2+} ---- > Cu + Zn^{2+}$

In the reaction, $Cu^{2+}$ is reduced according to the following: $Cu^{2+} + 2 e^- -- > Cu$

While Zn is oxidized according to the following: $Zn - 2e^- --- > Zn^{2+}$

Thus, giving the overall equation of; $Zn + Cu^{2+} ---- > Cu + Zn^{2+}$

More oxidation-reduction equations can be found here: brainly.com/question/13699873

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5 0

1 year ago

Acid strength in a series of h−a molecules increases with increasing size of

-BARSIC- [3]

Hello there!

The statement that Acid strength in a series of H-A molecules increases with increasing size of A is True.

When only the size is involved, increasing the size will increase the Acid strength because as size increases, the H-A bond will become weaker as the atoms will be farther apart. Acid strength is related to the ability to release H⁺ ions and a weaker H-A bond will release H⁺ more easily.

Have a nice day!

8 0

2 years ago