a fixed luminous point in the night sky which is a large, remote incandescent body like the sun. or a conventional or stylized representation of a star, typically one having five or more points.
Answer:
Speed Unchanged.
Explanation:
As work is defined as a product of force over a distance. If the distance in altitude is constant = 500km, there's 0 change in distance and force, no work would be done by the gravitational force.
Since potential energy of the satellite is unchanged, unless there's additional internal energy source, the kinetic energy would remain unchanged, so would its speed.
The Volume of the ice block is 5376.344 cm^3.
The density of a material is define as the mass per unit volume.
Here, the density of ice given is 0.93 g/cm^3
Mass of the ice block given is 5 kg or 5000 g
Now calculate the volume of the ice block
density=mass/volume
0.93=5000/Volume
Volume =5376.344 cm^3
Therefore the volume of ice block is 5376.344 cm^3
Answer:
The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).
Explanation:
The gravitational force is the force of mutual attraction that two objects with mass experience.
The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:
where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives the name of constant of gravitation.
If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:
F'=4*F
<u><em>
The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).</em></u>
To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as , the relation with the final volume as
Initial temperature =
Let T be the temperature after expanding by the formula of volume expansion
we have,
Where is the volume coefficient of copper
Therefore the temperature is 53.06°C