<h2>
Answer:</h2>
y = 
x + 3
<h2>
Step-by-step explanation:</h2>
As shown in the graph, the line is a straight line. Therefore, the general equation of a straight line can be employed to derive the equation of the line.
The general equation of a straight line is given by:
y = mx + c <em>or </em>-------------(i)
y - y₁ = m(x - x₁) -----------------(ii)
Where;
y₁ is the value of a point on the y-axis
x₁ is the value of the same point on the x-axis
m is the slope of the line
c is the y-intercept of the line.
Equation (i) is the slope-intercept form of a line
Steps:
(i) Pick any two points (x₁, y₁) and (x₂, y₂) on the line.
In this case, let;
(x₁, y₁) = (0, 3)
(x₂, y₂) = (4, -2)
(ii) With the chosen points, calculate the slope <em>m</em> given by;
m = 
m = 
m =
(iii) Substitute the first point (x₁, y₁) = (0, 3) and m = into equation (ii) as follows;
y - 3 = (x - 0)
(iv) Solve for y from (iii)
y - 3 = x
y = x + 3 [This is the slope intercept form of the line]
Where the slope is and the intercept is 3
Answer:
6:10
Step-by-step explanation:
To solve this problem, find the time 2 hours and 14 minutes before 8:24.
2 hours before 8:24 is 6:24.
14 minutes before 6:24 is 6:10.
Therefore, Nina started skating at 6:10.
Answer:
part a: she borrowed 3,700
part b: she would pay 555 interest
Step-by-step explanation:
The complete question in the attached figure
Let
x-----------------> number of <span>paintbrushes----------- > $0.95 each
y---------------- > number of jar of paint-------------- > $0.99 each
we know that
0.95x+0.99y = </span><span>$4.87
</span><span>
using a graph tool
</span>the solution will be a pair of coordinates that are whole numbers -- > see the attached figure
<span>
the solution is the point (2,3)
x=2---------------------- > </span>number of paintbrushes
y=3---------------------- > number of jar of paint
the answer is
number of paintbrushes=2
number of jar of paint=3<span>
</span>
Answer:
74 and 27
Step-by-step explanation:
let x and y be the numbers
x + y =101........eqn 1
x - y = 47.......eqn 2
solve simultaneously
from equation 2, make x the subject
x= 47 + y........eqn 3
put eqn 3 into eqn 1
(47+y) + y = 101
47 + 2y = 101
2y= 101 - 47
2y=54
y= 54/2
y= 27
put y=27 into eqn 3
x = 47 + 27
x = 74
