Answer:
There is an asymptote at x = 0
There is an asymptote at y = 23
Step-by-step explanation:
Given the function:
(23x+14)/x
Vertical asymptote is gotten by equating the denominator to zero
Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0
Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator
Coefficient of x at the numerator = 23
Coefficient of x at the denominator = 1
Ratio = 23/1 = 23
This means that there is an asymptote at y = 23
The answer to your question is 42. The rule is 5 or more go up 1 . If the number is 4 les stay where it is. hope this help.
Answer:
Step-by-step explanation:
first multiply 1 with 2+5i then multiply 2i with 2+5i and you will get
2+5i+4i+10i^2
then in the next step add 4i and 5i you will get 9i
in the next step put i^2=-1 and you will get -10
in the last step just substract 2-10 you will get -8 and 9i
and your answer will be -8+9i
Answer:
Step-by-step explanation:
Let the weight of the bag of sand with an unknown weight be given as "x" pounds. Then, the difference between the weight of an average bag of sand which is given to be as 22.3 pounds, is given as 
. Therefore, the absolute value function describing the difference between the weight of an average bag of sand and a bag of sand with an unknown weight will be given as: 
.
Let us represent this by f(x) or y. And thus, we get:
Answer;
The answer is the second; log ₁₂1/4
Explanation;
From the laws of logarithms, given an expression in the form;
Log ₓ y, where x is the base and y is the number, we can apply the change of base formula to a logarithmic expression to get;
Log y/log x, which are to base 10
Thus; Log₁₂1/4 = log 1/4/ log 12
