Apply the distributive property to create an equivalent expression.
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Answer:
Step-by-step explanation:
we know that
In this problem we have a exponential function of the form
where
y ----> represent the pool’s loss of water
x ----> the number of days
a is the initial value
a=25,700 gal
b ----> is the base
r=15%=15/100=0.15
b=(1-r)=1-0.15=0.85
The function is equal to
Let n be the total number of puffs. Now we can write:
Adding the fractional value of n, we get:
Simplifying and rearranging gives us:
Therefore we can simplify to get:
and finally
The fraction of the puff that are tuna is found from:
Adding the fractional value of n, we get:
Simplifying and rearranging gives us:
Therefore we can simplify to get:
and finally
The fraction of the puff that are tuna is found from: