Answer:
C(p) = 4,96 (in thousands of dollars)
l = 2980 $ invest in labor
k = 2980 $ invest in equipment
Step-by-step explanation:
Information we have:
Monthly output P = 450*l*k ⇒ k = P/450*l
But the production need to be 4000
Then k = 4000/450*l
Cost of production = l * k (in thousands of dollars)
C(l) = l + 4000/450*l
Taking derivatives (both members of the equation)
C´(l) = 1 - 400 /45*l² ⇒ C´(l) = 0 ⇒ 1 - 400/45l² = 0
45*l² - 400 = 0 ⇒ l² = 400/45
l = 2.98 (in thousands of dollars)
l = 2980 $ And
k = 400/45*l ⇒ k 400/45*2.98
k = 2.98 (in thousands of dollars)
C(p) = l + k
C(p) = 2980 + 2980
C(p) = 5960 $
is not included as a rational number !
<u>Step-by-step explanation:</u>
Here we have , following expressions & we need to identify which of the following is not a rational number . Let's find out:
We know that , Rational Number : A number which can be expressed in form of p/q , where q is not equal to zero !
Here Expressions are:
:
Let's evaluate this expression
⇒ 
⇒ 
Therefore , It is a rational number ! .
:
Let's evaluate this expression
⇒
Therefore , It is a rational number ! .
:
Let's evaluate this expression
⇒ 
⇒ 
Therefore , It is a rational number ! .
- :
Let's evaluate this expression
⇒
⇒ 
Therefore , It is not a rational number , as pi is included ! .
Answer:
0.920
Step-by-step explanation:
To calculate this, we proceed to the t-table
Using degree of freedom 5 and significance level of 0.2, the t-value is 0.920
Answer:
A and C
Step-by-step explanation:
i chose these bc they arwe the 2 reasonable ones
Answer:
Cubic equations and the nature of their roots
Just as a quadratic equation may have two real roots, so a cubic equation has possibly three. But unlike a quadratic equation which may have no real solution, a cubic equation always has at least one real root.
