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2 years ago

Use the listing method to represent the following set.

Mathematics

2 answers:

Dafna11 [192]2 years ago

7 0

The answer is c bc x is 3 and more

satela [25.4K]2 years ago

3 0

<h3>SoLuTiOn↝</h3>

Given:- {x | x I, x ≥ 3}

x is greater than and equal to 3

So, According To Question

x ≥ 3

= { 3,4,5,6,7,9......}

<h3><u>So Correct Option Will Be</u></h3>

<h3>Hope This Helps You</h3>

You might be interested in

Can somebody explain to me how they got 3^4(x) = 3^3(x+2)? Then explain what happened to the 3 in 3^4 and the 3 in 3^3? Please a

musickatia [10]

Answer:

x=6

Step-by-step explanation:

81^x = 27 ^(x+2)

81 = 3^4 and 27 =3^3 so replace 81 and 27 in the equation

3^4^x = 3^3^(x+2)

When we have a power to a power we can multiply the exponents

a ^b^c = a^(b*c)

3^(4x) = 3^(3*(x+2))

Since the bases are the same, the exponents have to be the same

a^b = a^c means b=c

4x = 3(x+2)

Now we can solve for x

Distribute

4x = 3x+6

Subtract 3x from each side

4x-3x = 3x-3x+6

x = 6

3 0

2 years ago

I need the answers for 3, 4, 5, and 6! thanks!!

Makovka662 [10]

Number 3 =32 us cups

4 0

2 years ago

4 friends have more than 7 stickers and less than 13 stickers they share the stickers evenly how many stickers NEED HELP

mash [69]

Well, there can be two answers. So, plus 3 other friends (4 people total) are sharing stickers.
To answer this, all you need to do is count by four.
4 is not greater than 7 so can not be the answer
4+4 or 8 IS greater than 7 and less than 13 so it can be the answer
4+4+4 or 12 IS ALSO GREATER THAN 7 and less than 13 so it can be the answer
4+4+4+4 is 16 and is greater than 13 so it cannot be the answer
SO it is either 8 or 12 stickers

3 0

2 years ago

Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)

adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0

2 years ago

Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

$y''+6y'+10y=0$

<u>Use Auxiliary Equation</u>

<u /> $m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

<u>General Solution</u>

<u /> $y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

1 year ago