Answer:
Explanation:
Let say the ball is projected at an angle with horizontal
So here two components of the velocity of the ball is given as
now the displacement in x direction is given as
in y direction it is given as
now from above two equations
Answer:
Explanation:
Givens
m = 942
F = 6731
t = 21 seconds
vi = 0
vf = ?
Formula
F = m * (vf - vi ) / t
Solution
6731 = 942*(vf - 0)/21 Multiply both sides by 21
6731 * 21 = 942*vf
141351 = 942*vf Divide by 942
141351/942 = vf
vf = 151 m/s
Answer:
h = 9.83 cm
Explanation:
Let's analyze this interesting exercise a bit, let's start by comparing the density of the ball with that of water
let's reduce the magnitudes to the SI system
r = 10 cm = 0.10 m
m = 10 g = 0.010 kg
A = 100 cm² = 0.01 m²
the definition of density is
ρ = m / V
the volume of a sphere
V =
V = π 0.1³
V = 4.189 10⁻³ m³
let's calculate the density of the ball
ρ =
ρ = 2.387 kg / m³
the tabulated density of water is
ρ_water = 997 kg / m³
we can see that the density of the body is less than the density of water. Consequently the body floats in the water, therefore the water level that rises corresponds to the submerged part of the body. Let's write the equilibrium equation
B - W = 0
B = W
where B is the thrust that is given by Archimedes' principle
ρ_liquid g V_submerged = m g
V_submerged = m / ρ_liquid
we calculate
V _submerged = 0.10 9.8 / 997
V_submerged = 9.83 10⁻⁴ m³
The volume increassed of the water container
V = A h
h = V / A
let's calculate
h = 9.83 10⁻⁴ / 0.01
h = 0.0983 m
this is equal to h = 9.83 cm
D - tertiary consumer
This is because it is the farther up to food chain.
C. Forces have mass and take up space