The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles
<h3>Balanced equation </h3>
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
2 moles of water were obtained from 1 mole of oxygen
<h3>How to determine the mole of oxygen needed </h3>
From the balanced equation above,
2 moles of water were obtained from 1 mole of oxygen
Therefore,
28 moles of water will be obtained from = 28 / 2 = 14 moles of oxygen
Thus, 14 moles of oxygen are needed for the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
Explanation:
Mg²⁺ is divalent , hence
Molecular weight / 2 = equivalent weight .
.25 moles = 2 x .25 equivalents = .5 equivalents .
Cl⁻ is monovalent so
molecular weight = equivalent weight
.50 mole = .50 equivalent
Total equivalent = .50 of Mg²⁺ + .50 of Cl⁻
= 1 equivalent .
Answer:
The new volume of gas would be 30 L.
Explanation:
This is an example of a Combined Gas Laws problem.
Answer:
e. all of these
Explanation:
Let us check all the given options one by one:
a.The nucleus is positively charged.
Yes it is correct since nucleus contain protons and neutrons and protons are positively charged.
b.The nucleus contains both charged and uncharged particles.
Yes because protons are positively charged and neutrons are neutral in nature.
c.The electrons contribute very little to the total mass of the atom.
Yes we know all the mass of the atom is considered in center and mass of electron is negligible as compared to protons and neutrons.
d.The electrons are located in the atomic space outside the nucleus.
Yes, its a known fact.
e. All of these.
Since , all given options are correct .
Therefore , option e. is right .