Answer:
Approx. 4⋅g.
Explanation:
Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.
Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.
Given the stoichiometry,
mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.
Why did I multiply the mass in this equation by 2? Am I pulling your leg?
Answer:
a) the minimun of acetic anhydride required for the reaction is 2.175 g (CH3CO)2O
b) V acetic anhydride = 2.010 mL
Explanation:
C6H4OHCOOH + (CH3CO)2O ↔ C9H8O4 + C2H4O2
⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH
⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O / mol C6H4OHCOOH ) = 0.0213 mol (CHECO)2O
⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O
b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O
The ribosomes are the ones delivering the products of the endoplasmic reticulum
Answer:
B
Explanation:
to conduct scientific exploration of the moon