Answer:
3.18 L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 0.985 atm
- Initial volume (V₁): 3.65 L
- Final pressure (P₂): 861.0 mmHg
Step 2: Convert P₁ to mmHg
We will use the conversion factor 1 atm = 760 mmHg.
0.985 atm × 760 mmHg/1 atm = 749 mmHg
Step 3: Calculate the final volume of the gas
Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 749 mmHg × 3.65 L/861.0 mmHg = 3.18 L
Answer: Tin (Sn)
Explanation: The electron configuration for tin (Sn) is shown in the picture. It's last electrons are:
5s^2 4d^10 5p^2
The valence electrons are in the 5th electron shell and include 2 each in the 5s and 5p orbitals.
There would be 67 left because you do
Blue litmus paper turns red in the presence of an acid. Therefore, it can be assumed that the substance in the beaker is an acid.
Acids have a pH level of less than 7. Consequently, it can be assumed that the substance has a pH level less than 7.
The specific heat capacity is intensive, and does not depend on the quantity.
We can categorize a property of the compound as either intensive or extensive when defining a particular aspect of it. The extent of a drug or compound is a quality that is influenced by the sample size used. However, the intense property is independent of the quantity (we can say that it is independent on the amount of the sample used). One such example of an intensive property is density.
The specific heat capacity of a substance or a compound describes the amount of heat (in Joules) needed to increase the temperature of one gram of the substance by 1 unit.
The specific heat capacity is independent on the amount of substance used, therefore, it is classified as an intensive property of a substance. The specific heat capacity will not depend on the mass of the given substance and it will be a constant value for each substance.
So the specific heat capacity is intensive, and does not depend on the quantity, but the heat capacity is extensive, so two grams of liquid water have twice the heat capacitance of 1 gram, but the specific heat capacity, the heat capacity per gram, is the same, 4.184 (J/g.K).
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