Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Answer:3ab^2 or 12ab^3
i think this is it
Step-by-step explanation:
To find a perimeter, add all sides together:
9) 12 + 12 + 8 + 8 = 20 + 20 = 40 in
10) 3 + 3 + 3 + 3 = 6 + 6 = 12 cm
To find area, multiply length and width, or base and height:
11) 3 x 6 = 18
12) 10 x 30 = 300 ft
13) 12 x 12 = 144 cm
14) 7 x 4 = 28 m
15)
Perimeter: 2(2) + 2(16) = 4 + 32 = 36
Area: 1 x 16 = 16
hope this helps
Answer:
I don't know how to do this. I'm so sorry that I couldn't help!!
Step-by-step explanation:
