What would the circumference be of a circle if the radius is 14

Mathematics

1 answer:

Fantom [35]2 years ago

4 0

C≈87.96 because C=2πr=2·π·14≈87.96459

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P + 46 = 94, what is p?

Natalka [10]

<h2>P is equal to:</h2>

48.

Because 46+48 equals 94.

You can easily find out equations to this by subtracting the 46 from 94 to see what p is equal to.

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1 year ago

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BARSIC [14]

Answer:

7/8=0.875 7/20=0.35 18/20=0.9 7/8=0.875 68/50=1.36 25/20=1.25 26/25=1.04 11/10=1.1 11/16=0.6875 9/16=0.5625 33/40=0.825 23/40=0.575 14/10=1.4 29/25=1.16 39/40=0.975

Step-by-step explanation:

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2 years ago

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A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

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2 years ago

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LenKa [72]

Answer: first answer choice (1/3) (p+45)

Step-by-step explanation:

to do this, factor out 1/3 from each element

so divide 1/3 p by 1/3 and 15 by 1/3

(1/3 p) / (1/3 ) = p

15 / (1/3) = 15 * 3 = 45

now put 1/3 outside of the parentheses

(1/3) (p+45)

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2 years ago