A size force of 5N will be exerted on Artl's foot.
This is because Newton's third law of motion, where in which an action occurs, a reaction will occur with the same amount of force, but reversed towards the direction of the area where the action occurred.
Answer:
Let's start by using the definition of acceleration. Acceleration is defined as the change in velocity over the change in time. In equation, that would be Δvelocity/Δtime. Based on the axes of the given graph, it shows the trend of position over time. So, the slope of the line and the curve shows the change of position over change of time, Δdistance/Δtime. In physics, this is the definition of speed or velocity. So, Maia is incorrect. Both curves show the speed or velocity of the object, and not acceleration. If the graph used a y-axis of velocity instead of position, then only at that instance, would be Maia be correct.
The difference between the two is, the straight line shows constant velocity while the curve line shows changing velocity.
Explanation:
There are few elements that can form 12 electron rather
than the usual 8. Therefore these are the possible answers:
Sulfur = 2Na + S --> Na2S <span>
Selenium = 2Na + Se --> Na2Se
<span>Tellurium = 2Na + Te --> Na2Te</span></span>
Answer: um is this a question or are you just telling people
Explanation:
Explanation:
At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 0.0721 atm
n=\frac{mass}{molar \;mass}n=
molarmass
mass
R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK
−1
mol
−1
T=?
Putting value in the given equation:
\frac{PV}{RT}=n
RT
PV
=n
density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=
0.082057338LatmK
−1
mol
−1
XT
2atmXmolarmass
0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=
0.082057338LatmK
−1
mol
−1
XT
0.0721atmX108.07g/mol
T = 365.2158727 K= 365 K
Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
