Answer:
option B
Explanation:
A spontaneous reaction drive favorable when enthalpy is decreasing and the entropy is increasing on the system. If that happens the reaction occurs spontaneously
Answer:
O: 3.41 / 3.41 = 1.00.
Explanation:
To find the simplest whole number ratio, divide each number by the smallest number of moles
Answer:
C. One mole of water was produced from this reaction.
Explanation:
- From the balanced equation:
<em>2H₂ + O₂ → 2H₂O,</em>
It is clear that 2 mol of H₂ react with 1 mol of O₂ to produce 2 mol of H₂O.
- So, if one mole of hydrogen was used in this reaction:
1/2 mol of O₂ was used in the reaction, and
1 mol of water was produced from this reaction.
- So, the correct statement is:
<em>C. One mole of water was produced from this reaction.
</em>
Answer:
290.82g
Explanation:
The equation for the reaction is given below:
2Al + 3H2SO4 -> Al2(SO4)3 + 3H2 now, let us obtain the masses of H2SO4 and Al2(SO4)3 from the balanced equation. This is illustrated below:
Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 +64 = 98g/mol
Mass of H2SO4 from the balanced equation = 3 x 98 = 294g
Molar Mass of Al2(SO4)3 = (2x27) + 3[32 + (16x4)]
= 54 + 3[32 + 64]
= 54 + 3[96] = 54 + 288 = 342g
Now, we can obtain the mass of aluminium sulphate formed by doing the following:
From the equation above:
294g of H2SO4 produced 342g of Al2(SO4)3.
Therefore, 250g of H2SO4 will produce = (250 x 342)/294 = 290.82g of Al(SO4)3
Therefore, 290.82g of aluminium sulphate (Al(SO4)3) is formed.
