2 years ago

This substance consists of two or more different elements chemically combined

Chemistry

1 answer:

kow [346]2 years ago

8 0

The substance would be referred to as a compound substance.

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How much heat is absorbed when 447 g of water , Cp = 4.184 J/goC, goes from 25.0 oC to 35.0 oC?

Digiron [165]

Answer:

The answer to your question is Q = 18702.5 J

Explanation:

Data

mass of water = m = 447 g

Cp = 4.184 J/g°C

Temperature 1 = T1 = 25°C

Temperature 2 = T2 = 35°C

Heat = Q = ? Joules

Process

1.- Write the formula to calculate heat

Q = mCp(T2 - T1)

2.- Substitution

Q = (447)(4.184)(35 - 25)

3.- Simplification

Q = (447)(4.184)(10)

4.- Result

Q = 18702.5 J

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2 years ago

What is the temperature of the freezing point of water in celsius?

LuckyWell [14K]

It is 0 gradus in celcius

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2 years ago

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When glucose is fermented, ethanol is formed together with ………………….

levacccp [35]

Answer:

carbon dioxide and oxygen

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When one metal mixes into the crystalline lattice of another it is called a(n) alloy compound chemical reaction heterogeneous so

bekas [8.4K]

the correct answer is alloy

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2 years ago

An unknown piece of metal weighing 95.0 g is heated to 98.0°C. It is dropped into 250.0 g of water at 23.0°C. When equilibrium i

lutik1710 [3]

Answer:

$C_{metal}=126.6\frac{J}{g\°C}$

Explanation:

Hello!

In this case, when two substances at different temperature are put in contact and an equilibrium temperature is attained, we can evidence that the heat lost by the hot substance (metal) is gained by the cold substance (water) and we can write:

$Q_{metal}=-Q_{water}$

Which can be also written as:

$m_{metal}C_{metal}(T_{EQ}-T_{metal})=-m_{water}C_{water}(T_{EQ}-T_{water})$

Thus, since we need the specific heat of the metal, we solve for it as shown below:

$C_{metal}=\frac{m_{water}C_{water}(T_{EQ}-T_{water})}{-m_{metal}(T_{EQ}-T_{metal})} \\\\C_{metal}=\frac{250.0g*4.184\frac{J}{g\°C}(29.0\°C-98.0\°C)}{95.0g(29.0\°C-23.0\°C)} \\\\C_{metal}=126.6\frac{J}{g\°C}$

Best regards.

7 0

2 years ago