You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.
You can use a modified dilution formula to calculate the volume of 30 % sugar.
<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3
Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt
(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar
30<em>x</em> + 25 = 20x + 100
10<em>x</em> = 75
<em>x</em> = 75/10 = 7.5
You're correct It's D :))))))))<span />
Answer:
C(s) + O2(g) 》CO2 (g)
Explanation:
to check CO2 is release mix the gas with quick lime you see colour is change
There are many scenarios in which the situation in question may take place, the rule is that for this to happen, the temperature and pressure of the gas must <em><u>change </u></em><em><u>by the same amount. </u></em>
As stated, the temperature and the pressure of the enclosed gas may change, in which they may <em><u>increase </u></em>or <em><u>decrease</u></em>, but the change must be by the same magnitude for each value. What this means is that is temperature increases by 5, so then must the pressure.
This is due to the relationship between the temperature and the pressure of an enclosed gas when using the combined gas law. The law takes the form of a fraction in which the pressure is found as part of the <u>numerator </u>and the temperature is part of the <u>denominator</u>, therefore, by increasing at the same rate, the final product and the volume will not be affected.
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