since airplane is thrown towards west with speed 6 m/s
while air is blowing with speed 8 m/s towards north
so here the net speed of air plane will be the resultant of airplane speed and wind speed always
SO here we can say it would be a combination of vector along west with must be of length 6 m/s and other vector is towards north with is of length 8 m/s
so correct answer must be 1st option
Here a cat is running at constant speed which is given as 10 km/h for 5s
So here the average speed is defined as total distance moved in total time interval
so here it is given by
since
here speed of cat is constant so it will remain the same
And hence the average speed and instantaneous speed at any instant for this duration will remain the same
so here answer would be
<em>average speed = 10 km/h</em>
<em>instantaneous speed = 10 km/h</em>
I believe the answer is the second option.
Gravitational potential energy can be calculated using the formula:
Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height
On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.
So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m
So we put that in and solve it.
Answer:
22 revolutions
Explanation:
2 rev/s = 2*(2π rad/rev) = 12.57 rad/s
The angular acceleration when it starting
The angular acceleration when it stopping:
The angular distance it covers when starting from rest:
The angular distance it covers when coming to complete stop:
So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions