If 68 minutes ago it (then) was three times as many minutes past 10 am (now)
x + 68 = 3 ×
×
(120 - x) →
→
x = 73 min
… if 68 minutes ago it (now) was three times as many minutes past 10 am (then)
x = 3 ×
×
[120 - (x + 68)] →
→
x = 39 min
… if 68 minutes ago it (then) was three times as many minutes past 10 am (then)
x + 68 = 3 ×
×
[120 - (x + 68)] →
→
x = 22 min
N equals to 2 so 4 plus 2 is 6 and that is the answer!!
Glad I could help. Have A Good day
Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)
Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points,
D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)
5 is your missing factor because 9*5=45 btw dont use x for multiplication use this *