Answer:
see in the graph, the circle has: the centre I(3; -2)
r = 3
=> the equation: (x - 3)² + (y + 2)² = 9
Answer:
D
Step-by-step explanation:
Given the 2 equations
y = x - 5 → (1)
y = x² - 5x + 3 → (2)
Substitute y = x² - 5x + 3 into (1)
x² - 5x + 3 = x - 5 ← subtract x - 5 from both sides
x² - 6x + 8 = 0 ← in standard form
(x - 2)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 4 = 0 ⇒ x = 4
Substitute each of these values into (1) for corresponding values of y
x = 2 → y = 2 - 5 = - 3 ⇒ (2, - 3 )
x = 4 → y = 4 - 5 = - 1 ⇒ (4, - 1 )
Answer with Step-by-step explanation:
We are given that
We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).
LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0
Right hand limit =RHL when x> 2
Substitute
x=2+h
LHL=RHL=
f(2)=1
Hence, function is discontinuous at x=2