Answer:
Step-by-step explanation:
First=4
Second=1 time
Third=3 turning points
Hope this helps you good luck
Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.
When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor.
x + 1
------------------------------------
x+1| x²+2x+1
- x²+x
----------------------
x +1
- x +
------------
0
Explanation: The y axis is the line that goes up and down, vertical. The x axis is the line that goes straight across, horizontal. So, when looking for intercepts we have to see what numbers your graphed line goes through.
Make sure when you are writing your points you write it in (x,y) form. If you don't it will be wrong.
So, for our x intercept it would be -7,0.
This is because your graphed line goes through x at -7 and it has no y, so that would be 0.
For your y intercept, it would be 0,2
This is because our line does not go through x, so we make that 0. It does go through y at 2.
Hope this helps :)
If you need elaboration on anything let me know. I know sometimes with math it is kind of hard to explain through typing.
Answer:
Step-by-step explanation:344x-5-p-0-9-but=pmc+m2 something like that
