Iron powder and sulfur powder combined physically; therefore, they retained their individual properties.
Answer:
120.37 g
Explanation:
Mg = 24.31 g
S = 32.06 g
4 O = 16 X 4 = 64 g
Therefore, MgSO4 is (24.31 + 32.06 + 64) g = 120.37 g
Answer:
32.1 × 10²³ formula units of CuCl₂
Explanation:
Given data:
Number of moles of CuCl₂ = 5.33 mol
Number of formula units of CuCl₂ = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of any substance contain 6.022 × 10²³ formula units thus,
5.33 moles of CuCl₂ = 5.33 ×6.022 × 10²³ formula units
32.1 × 10²³ formula units of CuCl₂
Answer:
Explanation:
a) The mass of the reactants is 2.36 grams, and the mass of the products is 1.57 grams plus the mass of the carbonic acid. Thus, using the law of conservation of mass, we get the mass of the carbonic acid is 2.36 - 1.57 = 0.79 grams.
b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%
