Answer:
6.24%
Explanation:
Molality by definition means a measurement of the number of moles of solute in solution with 1000 gm or 1Kg solvent. Notice the difference that Molarity is defined on the volume of solution and Molality on the mass of solvent.
So, An aqueous solution of iron(II) iodide has a concentration of 0.215 molal.
means 0.215 moles are present in 1 Kg of solvent.
The molar mass of Fe2I = 309.65 g / mole
mass of FeI2 = moles x molar mass
= 0.215 x 309.65
=66.57 gm
mass % of FeI2 = mass of FeI2 x 100 / total mass
= 66.57x 100 / (1000 +66.57)
= 6.24%
The average density of the peat moss in units of g/cm³ is 2.52 g/cm³
<h3>How to convert 40 lb to grams (g)</h3>
We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:
1 lb = 453.592 g
Therefore,
40 lb = (40 × 453.592) / 1 lb
40 lb = 18143.68 g
<h3>How to convert 1.9 gal to cm³</h3>
We can convert 1.9 gal to cm³ as follow:
1 gal = 3785.41 cm³
Therefore,
1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal
1.9 gal = 7192.279 cm³
<h3>How to determine the density </h3>
The density can be obtained as follow:
- Mass = 18143.68 g
- Volume = 7192.279 cm³
- Density =?
Density = mass / volume
Density = 18143.68 / 7192.279
Density = 2.52 g/cm³
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Answer:
Option A (0.043 g) is the correct answer.
Explanation:
Given:
= 43 mg
As we know,
then,
⇒
Thus, the above is the correct alternative.
1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.
Hence, in this case the mass of carbon in 8.46 g of CO2:
(12/44) × 8.46 = 2.3073 g
1 mole of water contains 18 g, out of which 2 g is hydrogen;
Therefore, 2.6 g of water contains;
(2/18) × 2.6 = 0.2889 g of hydrogen.
Therefore, with the amount of carbon and hydrogen from the hydrocarbon we can calculate the empirical formula.
We first calculate the number of moles of each,
Carbon = 2.3073/12 = 0.1923 moles
Hydrogen = 0.2889/1 = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing with the smallest number value;
Carbon : Hydrogen
0.1923/0.1923 : 0.2889/0.1923
1 : 1.5
(1 : 1.5) 2
= 2 : 3
Hence, the empirical formula of the hydrocarbon is C2H3