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2 years ago

Find the slope of all line from the equation 8x - 8y =16

Mathematics

1 answer:

Artemon [7]2 years ago

4 0

Answer:

slope = 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

8x - 8y = 16 ( subtract 8x from both sides )

- 8y = - 8x + 16 ( divide all terms by - 8 )

y = x - 2 ← in slope- intercept form

with slope m = 1

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Artyom0805 [142]

Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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2 years ago

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liubo4ka [24]

Answer:

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$y=-4$

Step-by-step explanation:

$4x+5y=-8$ ----------- (1)

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Adding equation (1) and (2)

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2 years ago

Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the

Ivan

Let $L$ be the line given by the vector equation

$(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}$ .

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by $\Pi_1$ . This is,

$\\\\\Pi_1 : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\$

We observe that $\vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0)$ . Therefore, the vector equation of $\Pi_1$ defines a plane and $\vec{N}$ is a normal vector to $\Pi_1.$

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2 years ago

Find the slope of all line from the equation 8x - 8y =16​

Find the slope of all line from the equation 8x - 8y =16